Tuesday, December 29, 2020

Difference between primary alcohols, secondary alcohols and tertiary alcohols

 Objectives:

1. To study the physical and chemical properties of alcohols

2. To identify the two unknown liquids from their experimental observations

3. To study the difference between primary alcohols, secondary alcohols and tertiary alcohols.

Introduction:

The hydrocarbon chains that attached with a hydroxyl group, OH- to a carbon atom are known as alcohols. If the carbon atom is bonded to three hydrogen in addition to the OH-, the alcohol is called methanol. Methanol, CH3OH is the most simple alcohol molecule. The category of the alcohol is classified as three groups which are primary (1 ) alcohol, secondary (2 ) alcohols and tertiary (3 ) alcohol. If the alcohol bonded to one alkyl group, the alcohol is primary alcohol. The secondary alcohol is defined as the alcohol which one of the carbons is bonded to two alkyl groups and one hydrogen atom. If one of the carbons in alcohol is bonded to three alkyl groups is called tertiary alcohol.

All these alcohols share some similar characteristics but other characteristics are different owing to their different molecular structures. For physical properties, the size of alcohol determines its boiling point. Usually, the larger the size of the alcohol, the higher the boiling point. This is because the bigger the size of the molecules, the stronger the Van der Waals force between the alcohol molecules. So, more heat energy is needed to be absorbed in order to break down the intermolecular force between each alcohol molecules. Hence, the boiling point of the alcohols increases with the size of the alcohols. The solubility of the alcohol is depends on the size of molecules. Small alcohols are water soluble because the hydroxyl group can form hydrogen bond with water molecules. But, as the size of the alkyl group increases, the solubility of alcohol in water decreases as the hydrophobic property of alcohol increases. For example, if the carbon molecules in alcohol more than six per molecule, the particular alcohol definitely are not soluble in water. This is the result of the alkyl group disrupting the hydrogen bond among the water molecules. If the disruption becomes larger enough, the water molecules will repel the alcohol molecules effectively to reestablish hydrogen bonding.

The classification of an alcohol as primary, secondary or tertiary (see above) affects the chemical properties of the alcohols. Due to their different classes, the alcohols may give out different chemical properties when they react with the same compounds. Based on their chemical properties, we are able to differentiate among the classes of alcohols. Generally, Lucas test and chromic acid test is the two common tests that we always use to distinguish and categorize the classes of alcohols.

Lucas test

Water soluble alcohols are always tested by using the Lucas reagent to differentiate among the primary, secondary, and tertiary alcohols. This test depends on the appearance of an alkyl chloride as an insoluble second layer. Lucas reagent is the mixture of zinc chloride and hydrochloric acid. Zinc chloride is a Lewis acid which is added with hydrochloric acid to make its property becomes more acidic. The tertiary alcohol (water soluble) reacts with Lucas reagent almost immediately to form an alkyl chloride which is insoluble in the aqueous solution. The formation of a second layer liquid phase in the test tube almost as soon as the alcohol initially dissolves is indicative of a tertiary alcohol. The secondary alcohol reacts slowly with Lucas reagent, and it gives a second phase after heating for 10 minutes whereas the primary alcohol and methanol do not react with Lucas reagent under normal condition. The chemical equation is as shown below (if the reaction takes place)

ZnCl2

R-OH + HCl     ------------------>    R-Cl + H2O

Chromic acid test

Chromic acid is a strong oxidizing agent which uses to oxidize the alcohols. This test is based on the reduction of chromium (VI) ions to chromium (III) ion. When chromic acid reacts with alcohols, the change in colour of the solution from red-brown to green is a positive test. Primary alcohols are oxidized to carboxylic acid by chromic acid. The Cr6+ in the chromic acid which is red-brown is reduced to green Cr3+; secondary alcohols are oxidized to ketones by the reagent with the same colour change. Tertiary alcohols are not oxidized at all by the chromic acid. Hence, this reaction can be used to distinguish tertiary alcohols form primary and secondary alcohols.For tertiary alcohols, the alcohols would not be oxidized by the reagent. Hence, this test is used to distinguish the tertiary alcohols from primary and secondary alcohols.

 

Reaction with sodium metal

The acidic properties of alcohol can be shown by adding the sodium metal into alcohol. The alcohols are weak acids when they react with sodium metal. The hydroxyl group can act as a porton donor to form an alkoxide ion. Alkoxide ions dissolved in alcohol are strong bases which can be prepared by the reaction of an alcohol with sodium metal. Hydrogen gas is released by the reaction.

2 R-OH + 2 Na  -------> 2 R-O-Na+ + H2

The hydrogen gas can be collected and tested by using a burning wooden splinter. A pop sound will be produced.

Apparatus: test tube, measuring cylinder, droppers

Materials: ethanol (C2H5OH), isopropyl alcohol (C3H7OH), t-butyl alcohol (C4H9OH), Lucas reagent (mixture of concentrated HCl and ZnCl), chromic acid (H2CrO4), sodium metal

Procedure:

A. Solubility of alcohols

1. In three separate dry test tubes, ethanol, isopropyl alcohol and t-butyl alcohol are added into each test tube.

2. Water is added to each tubes, the contents are mixed and observed.

3. The results are recorded in a table.

4. The above procedures are repeated with two unknown liquids and observations are being made.

B. Lucas test

1. Ethanol, isopropyl alcohol and t-butyl alcohol are added into separate dry test tubes and Lucas reagent is added at room temperature.

2. The tubes are closed with a cork, the tubes are shaken and the length of time it takes for the mixture to become cloudy or separate two layers.

3. The results are recorded.

4. The above procedures are repeated with the two unknown liquids and observations are being made.

C. Chromic acid test

1. Ethanol, isopropyl alcohol and t-butyl alcohol are added into separate dry test tubes.

2. A small piece of sodium metal is added and any reactions occur are noted.

3. The step 1 and step 2 are repeated with two unknown liquids and any observations are made.

Results:

Part A

Table 1 The solubility of alcohols and their observations

Alcohols

Observation

Reaction equations(if any)

Deduction/conclusion/discussion

Ethanol

Soluble in water to form colourless solution

C2H5OH (aq) + H2O (l) ---> C2H5O- (aq)+ H+(aq)

Soluble in water

Isopropyl alcohol

Soluble in water to form colourless solution

C3H7OH (aq) + H2O (l)  ---> C3H7O- (aq) + H+ (aq)

Soluble in water

t-butyl alcohol

Soluble in water to form colourless solution

C4H9OH (aq) + H2O (l) -----> C4H9O- (aq) + H+ (aq)

Soluble in water

Unknown A

Soluble in water to form colourless solution

-

Soluble in water

Unknown B

Soluble in water to form colourless solution

-

Soluble in water

 

Part B

Table 2 The reaction between alcohols and Lucas Reagent

Alcohols

Observation

Reaction equations(if any)

Deduction/conclusion/discussion

Ethanol

Yellowish solution remains unchanged after heating.

 

No reaction between ethanol and Lucas reagent.

Isopropyl alcohol

Yellowish solution remains unchanged within 10 minutes, but turns into cloudy solution after heating.

C3H7OH (aq) + HCl (aq)  -----> C3H7Cl (aq) + H2O (l)

The reaction between isopropyl alcohol and Lucas reagent occur after heating for 10 minutes.

t-butyl alcohol

Cloudy solution is formed immediately and two layers are formed. Upper layer is clear while lower layer is cloudy.

C4H9OH (aq) + HCl (aq) C4H9Cl (aq) + H2O (l)

The reaction between t-buytl alcohol and Lucas reagent is instant reaction.

Unknown A

Yellowish solution remains unchanged within 10 minutes, but turns into cloudy solution after heating.

 

Unknown A is isopropyl alcohol because it has the similar reaction with it.

Unknown B

Cloudy solution is formed immediately and two layers are formed. Upper layer is clear while lower layer is cloudy.

 

Unknown B is t-butyl alcohol because it has the same reaction with it.

Part C

Table 3 The reaction of alcohols with chromic acid

Alcohols

Observation

Reaction equations(if any)

Deduction/conclusion/discussion

Ethanol

The solution turns from colourless to green

3 CH3CH2OH + 2 CrO4+ 10 Hà 3 CH3CHO + 2 Cr3+ +8 H2O

 

Ethanol is oxidized by the chromic acid.

Isopropyl alcohol

Two layers are formed. Upper layer is green while lower layer is black.

C3H7OH (aq) + H2CrO4(aq) -----> C2H6CO (aq) + Cr2(SO4)3(aq) + H2O(l)3 (CH3)2CHOH + 2 CrO4+ 10 Hà3 (CH3)2CO + 2 Cr3+ +8 H2O

 

Isopropyl alcohol is oxidized by the chromic acid.

t-butyl alcohol

Two layers are formed. Then, the precipitate dissolves in solution to become reddish brown solution.

-

No reaction.

Unknown A

Two layers are formed. Upper layer is green while lower layer is black.

 

Unknown A is isopropyl alcohol because it has the similar reaction with isopropyl alcohol.

Unknown B

Two layers are formed. Then, the precipitate dissolves in solution to become reddish brown solution.

 

Unknown B is t-butyl alcohol because it has the similar reaction with t-butyl alcohol.

Part D

Table 4 The reaction between alcohols and sodium metal

Alcohols

Observation

Reaction equations(if any)

Deduction/conclusion/discussion

Ethanol

Bubbles of colourless gas released quickly. A pop sound is produced when tested with burning wooden splinter.

2C2H5OH (aq) + 2Na(s) ------> 2C2H5ONa (aq) + H2(g)

Many of hydrogen gas is being produced from the reaction between ethanol and sodium metal.

Isopropyl alcohol

Bubbles of colourless gas released slowly. A pop sound is produced when tested with burning wooden splinter.

2C3H7OH (aq) + 2Na(s) -----> 2C3H7ONa (aq) + H2(g)

Small amount of hydrogen gas is being produced from the reaction between isopropyl alcohol and sodium metal.

t-butyl alcohol

Bubbles of colourless gas released very slowly. A pop sound is produced when tested with burning wooden splinter.

2C4H9OH (aq) +

2Na (s) ------> 2C4H9Ona (aq) +

H2 (g)

Less hydrogen gas is being produced from the reaction.

Unknown A

Bubbles of colourless gas released slowly. A pop sound is produced when tested with burning wooden splinter.

 

Unknown A is isopropyl alcohol because it has the similar reaction with isopropyl alcohol.

Unknown B

Bubbles of colourless gas released very slowly. A pop sound is produced when tested with burning wooden splinter.

 

Unknown B is t-butyl alcohol because it has the similar reaction with t-butyl alcohol.

Discussion:

This is because all of them, ethanol, isopropyl alcohol and t-butyl alcohol are short alkyl chain alcohols. Alcohols can soluble in water is because of the presence of the hydroxyl group (-OH) in the compounds. The hydroxyl group can form hydrogen bond with the water molecules and thus make it soluble in water.imageThe solubility of alcohols in water are always depends on their structure and size. When the sizes of alcohols increase, the solubility of alcohols in water will decrease. This is because the bulky groups are highly hydrophobic and tend to block the water molecule from nearing alcohol and stabilize it. This is the result of the alkyl group disrupting the hydrogen bond among the water molecules. If the disruption becomes larger enough, the water molecules will repel the alcohol molecules effectively to reestablish hydrogen bonding. Usually, the number of carbon per molecule is more than six are not soluble in the water.

Based on the properties of solubility of alcohols in water, this information is not enough for us to differentiate clearly the classes of alcohols which are being used in the experiment. So, Lucas test is used to distinguish among the primary, secondary, and tertiary alcohols. For Lucas test, the formation of two layers (aqueous layer and cloudy layer) is known as a positive test. The second layer (cloudy layer) formed is alkyl chloride which is insoluble in the aqueous solution because all the alkyl halides molecules are insoluble in the water. The alkyl chloride produced from the reaction is not water soluble and causes cloudiness (emulsion) to form in the aqueous solution. When ethanol is added with Lucas reagent, the yellowish solution is still remains the same before and after heating. This is because primary alcohol does not react with Lucas reagent. Besides, isopropyl alcohol does not react with Lucas reagent before heating but it does turns to cloudy solution after heating for 10 minutes. The reason is the reaction between Lucas reagent and secondary alcohol is slow. For tertiary alcohol (t-butyl alcohol), the reaction of alcohol with Lucas reagent is very fast which can be known as an instant reaction. The reaction that takes place on the Lucas test is a SN1 nucleophilic substitution. The alcohols with the properties of generating a stable carbocation intermediates will undergo the particular reaction. The OH group of the alcohol attracts the H in hydrochloric acid to form oxonium ion and leave the group (form water). The carbocation intermediate is formed and tends to react with Cl- (nucleophile) to produce the alkyl halide product. The mechanism of SN1 nucleophilic substitution is shown as diagram below:

image

The purpose of chromic acid test used in this experiment is to distinguish the primary and secondary alcohols from the alcohols group. In the reaction between alcohols and chromic acid, the chromic acid is being reduced which the chromium (VI) ions, Cr6+ reduced to become chromium (III) ion, Cr3+. The positive test for chromic acid is represented by the change in colour from orange to green-blue. In the test tube with ethanol, the colourless alcohol is turned to green solution because the chromium (IV) ions, Cr6+ are being reduced by ethanol. In the test tube containing isopropyl alcohol, two layers of colour are formed. The upper layer is green whereas the lower layer is black. This is shows that the isopropyl reacted with the chromic acid due to the secondary alcohol is readily to be oxidized. The black layer actually is the dark blue colour, it is hard to differentiate because the light is not enough in the laboratory. The t-butyl alcohol would not oxidized by the chromic acid since the tertiary alcohol is a highly oxidized alcohol. This is shown by the formation of reddish brown precipitate. The chemical equation for the reaction is shown as below:

Ethanol: 3 CH3CH2OH + 2 CrO4+ 10 Hà 3 CH3CHO + 2 Cr3+ +8 H2O

Isopropyl alcohol: 3 (CH3)2CHOH + 2 CrO4+ 10 Hà3 (CH3)2CO + 2 Cr3+ +8 H2O

 

The general mechanism for the reaction is shown below:

imageHydrogen ions will be attracted to one of the oxygen atom in the chromic acid that is double bonded to chromium. The lone pair electrons from hydroxyl group of alcohols will then attack the chromium ion and form a chromate intermediate. The hydrogen on the hydroxyl group of alcohols will then leave as hydrogen ion and combine with the oxygen atom that is previously attacked by a hydrogen ion. A water molecule will come and attack α-hydrogen on the alcohol and produce hydronium ion, forming C=O double bond. A water molecule will leave the chromate intermediate and the carbonyl product is formed. Since the oxidation of alcohol requires at least one hydrogen atom to be presence on α-carbon, thus tertiary alcohol cannot be oxidized because it does not have the α-hydrogen. This explains why t-butyl alcohol does not change the color of the chromic acid which is red brown to green. The precipitate formed at the beginning may be because of the formation of chromium trioxide precipitate.

The last test in this experiment is the reaction of sodium metal with alcohols. All the different classed of the alcohol are able to react with the sodium metal since all of them have OH group. According to the Lewis Bronsted Theory, a Bronted acid is a proton donor. In this case, alcohol acts as a proton donor which donates H+ into the solution while the sodium metal acts as a strong base. A strong base can deprotonates the alcohol to yield an alkoxide ion (R-O). The H in OH group will be substituted by sodium ion to form sodium alkoxide, R-O-Na+. The reaction between an acid and an active metal in group I element definitely will produce hydrogen gas as the product as the metallic sodium reduces proton to form hydrogen gas. The evidence is shown by the release of bubbles of colourless gas from the reaction between sodium metal and alcohol. The release of hydrogen gas can be collected and tested with a burning wooden splinter. A pop sound will be produced as the hydrogen gas is an explosive gas. The chemical equation of alcohols and sodium metal is shown as the diagram 1 below:

2C2H5OH (aq) + 2Na(s) 2C2H5ONa (aq) + H(g)

2C3H7OH (aq) + 2Na(s) 2C3H7Ona (aq) + H(g)

2C4H9OH (aq) + 2Na (s) 2C4H9Ona (aq) + H2 (g)

Diagram 1 The reaction between alcohols with different classes with sodium metal

The acidity of the alcohol can be determined by the rate of gas evolution in this experiment. The more the gas released from the reaction, the more acidic the properties of alcohol. The acidity of alcohols decreases as the number of carbon in bulky alkyl group that bonded to OH group increases. Since alkyl group is electron releasing group, the more bulky the alkyl group, the stronger the electron donor effect. Thus, the negative charge density on the O atom in and proton are less readily to be released. The second reason is the bulky groups are highly hydrophobic and tend to block the water molecule from nearing alcohol and stabilize it. The alcohols are arranged in order of increasing acidity of alcohol as below:

t-butyl alcohol < isopropyl alcohol < ethanol

Acidity increasing

 

Sunday, December 13, 2020

Produce cyclohexene through the acid catalyzed elimination of water from cyclohexanol

  

Objectives:

1. To produce cyclohexene through the acid catalyzed elimination of water from cyclohexanol

2. To understand mechanism involved in the reaction

3. To learn the technique of distillation

Introduction:

Dehydration is defined as a process of removing water from a substance. The loss of water from a molecule is called dehydration which is exactly opposite with the process of hydrolysis. Dehydration is an elimination reaction of an alcohol involves the loss of an OH from one carbon and an H from an adjacent carbon. Overall, this amounts to the elimination of a molecule of water, resulting in a pi-bond formation of an alkene or alkyne. In most of the dehydration of alcohol, heat and catalyze are needed in the reaction. Sulphuric acid (H2SO4) and phosphoric acid (H3PO4) are the most commonly used acid catalysts.

The dehydration process can be carried out by in two ways. The first way is heating a mixture of alcohol and dehydrating agent in a distilling flask and collecting the olefin (also known as alkene) from the mixture. The second way is passing the alcohol vapour through a heated tube packed with the dehydrating agent at 350°C. The collecting the olefin as it emerges from the tube. The chemical equation for dehydration of alcohol to form alkene and water is shown as below diagram:

clip_image004

For the dehydration of alcohol, the alkene is formed in the reaction. At the same time, the side products are produced from the reaction such as dicyclohexyl ether, polymer, mono and dicyclohexyl sulphate abd degradation products (carbon and carbon dioxide). In many cases, the phosphoric acid is used in the dehydration of alcohol instead of using sulphuric acid due to two reasons. The one of the reason is the lost of organic compound can be minimize through oxidation of phosphoric acid. In addition, the product is being produced without contamination with volatile decomposition products such as sulphurous acid.

Apparatus: Round-bottomed flask(50ml), take off distillation adapter, condenser, thermometer, electric flask heater

Materials: boiling chips, cyclohexanol, cyclohexene, 85% conc. Phosphoric acid, anhydrous magnesium sulpahte

Procedure:

1. Cyclohexanol and conc.(85%) phosphoric acid are added in a round bottomed flask and is mixed together by swirling.

2. Several boiling chips are added, the flask is clamped to a ring stand at electric flask heater height attached with a take off distillation adapter, a thermometer, a condenser and a small receiving flask as shown in the diagram below.

clip_image006

3. The mixture is heated and distillate boiling in the range 85°C-90°Cis obtained.

4. When the distillate is exhausted, the heat is increased gradually. Using the same receiver, the distillate boiling in the range of 90°C - 100°C is collected.

5. The two layers in the receiving flask are tested by adding the distilled water. With the aid of a 9-disposable pipette, the aqueous layer is drawn off and is being discarded.

6. The organic layer is dried up with anhydrous magnesium sulphate.

7. The drying agent is removed by filtering the mixture through a cotton wool plug wedged into the constricted part of a small funnel.

8. The filtrate is collected round bottom flask or small distilling flask. Boiling chip is added to the dried product and distil it through a take off distillation adapter packed with a few small wads of coarse steel wool.

9. The product boiling is collected in the range 3 below and 2 above the boiling point of cyclohexene (83°C) in a tarred bottle.

10. The yield in grams is calculated and the product is submitted to instructor.

Result and calculation:

Weight of cyclohexanol = 10.0060g

Weight of dry conical flask = 51.2460g

Weight of dry conical flask + weight of cyclohexene = 56.2281g

Experimental weight of cyclohexene = 4.9821g

clip_image004[1]

Number of mole of C6H11OH =

clip_image010

= 0.09996 mole

1 mole of C6H11OH produces 1 mole of C6H12

0.09996 mole of C6H11OH produces 0.09996 mole of C6H12

Theoretical weight of C6H12 = 0.09996 mole X 84.096 g/mol

= 8.4066g

Yield percentage =

 clip_image012

= 59.26%

Discussion:

In this experiment, the cyclohexanol solution is being used in the dehydration process. The cyclohexanol is a six carbon aromatic hydrocarbon which one of the hydrogen atoms, H is substituted by one hydroxyl group, OH-. Due to the low melting point, the cyclohexanol appear in liquid form at room temperature. The dehydration process of alcohol will convert cyclohexanol which the hydroxyl group, OH- will be removed to become cyclohexene. Cyclohexene is a six carbon aromatic hydrocarbon with a single double bond in the molecule.

The solution is added with concentrated phosphoric acid in a round bottomed flask and is mixed together by swirling. The phosphoric acid is added as catalyze as such increase the rate of reaction in dehydration without affects the particular chemical reaction. The boiling chips are added into the solution in order to prevent over boiling of the solution. The boiling chips are small, insoluble, and porous stones made of calcium carbonate or silicon carbide. There are a lot of pores inside the boiling chips which provide cavities both to trap air and to provide spaces to allow bubbles of solvent can be form. When boiling chips are heated, it will release tiny bubbles which can prevent boiling over. Boiling over of solvent will cause lost of solution which may lead to inaccurate result to be obtained.

The heating of mixture is carried out in a fractional distillation apparatus. As the mixture is heated, the alkene and water are produced as the products in the reaction. Besides, the side product and impurities of the reaction will be produced at the same time. The temperature of mixture when heating is fluctuated. During the temperature 80°C, the temperature of mixture drops suddenly by 2°C and the temperature remained at 78°C constantly for few seconds. This is because some impurities or side products are being produced in the mixture which may have the boiling point of 78°C. The temperature of mixture drops suddenly because the heat being is absorbed which used to break down the bonding of the side products. When the boiling point is reached, then temperature of mixture remains constant as the state of the side products are converted from liquid form to gaseous form. The temperature of mixture is increases until 107°C after all the side products are being converted.

The temperature of mixture is reached to maximum at 107°C. This temperature is known as the activation temperature which the cyclohexanol start to be dehydrated. The temperature of mixture drops to 83°C and remains constant. This phenomenon takes place because the cyclohexene with lowest boiling point will tends to be distilled first before the higher one. The temperature remains unchanged because the heat is being absorbed to break down the bond between cyclohexene molecules. In all the distillation process, some of the product will be lost since it is hold up in the apparatus which reduce the product yield. In order to maximize the yield, the mixture is continued to be heated at higher temperature range which more than the boiling point of cyclohexene. When the mixture is heated at 90°C-100°C, the water in the mixture will push over the products into the receiving flask along the condenser. The products produced are collected in the same receiving flask.

Then, the receiving flask containing cyclohexene, water and small amount of the impurities. Two layers liquid are present in the receiving flask, one drop of distilled water is added into flask in order to determine the location of aqueous layer. Since the water droplet mix with the lower layer, so the upper layer is determined as cloudy solution while the lower layer is aqueous layer. The upper cloudy layer is cyclohexene with some impurities and water inside. The lower aqueous layer is removed and discarded. But, that is not easy to remove all the water in the receiving flask. So, anhydrous magnesium sulphate is being added. The purpose of adding of anhydrous magnesium sulphate is used to remove residual water in the organic solvent. The magnesium sulphate in the granular form will be preferable. It is known as drying agent in the organic solvent which are not dissolves in the solvent but drying the solvent. The magnesium sulpahte clump together with the water droplets as it solidified them. In another words, it is reacts with water to form hydrates which is their preferred form when water is available. An excess drying agent should be used to ensure that all the water in solvent is removed. If the water remains in the materials collected, it could interfere with the analysis.

Water has been successfully removed from the organic compound mixture, so it is very important to not reintroduce water into the mixture. The final distillation of unpurified cyclohexene must be done very carefully in order to obtain purified products. The temperature of mixture is heated until approximate 85.5°C since this temperature is the boiling point of cyclohexene and hence the pure cyclohexene could be obtained rapidly. The weight of the cyclohenexe is 4.23g.

Error of source includes the condenser and Liebig tubes are not rinsed with a little of distilled water, a little of ethanol and acetone to speed up drying process. So that, the water in the desired products would not presents. This is because some of the water droplets is hold up and stick on the wall of condenser and the second distillation will produce the contaminated cyclohexene.

 

Thursday, July 30, 2020

Dissolved oxygen (DO)

What is dissolved oxygen (DO)? 

Dissolved oxygen refers to the amount of oxygen level that present in the water or liquid sample. Dissolved oxygen level is very important to the aquatic life in a healthy ecosystem. Too much of oxygen may create algae bloom provided the high nutrient load present in the water, however too low of oxygen amount that present in water will make the fishes suffocating and eventually die. 

How do we measure DO in the water?

METHOD 1: Winkler titration method - conventional method

We can use Winkler titration to measure DO amount in the water sample that has been took and prepared manually from the site into water bottle. The Winkler titration method measures the DO amount in the water sample precisely, this is a method developed by Hungarian analytical chemist named Lajos Winkler in 1888. This method adding chemicals to the water sample to form an acidic solution by creating reaction with the oxygen that present in the water. Then we will add in the neutralizing agent to perform neutralization with titration and the amount of neutralizing agent required indicate the amount of the oxygen level in the water sample. Below is the diagram to show the Winkler titration in step by step. 


Although Winkler titration can deliver highly accurate result, but this method is laborious, time-consuming and highly susceptible to the interference. 


METHOD 2: Using in-situ DO meter

Alternatively, we can use DO meter that can provide instant result instead. A lot of researchers they prefer to use in-situ DO meter because the amount of oxygen in water sample may fluctuate across the time. The amount of oxygen may varies at different water level. The deeper the water level, the lesser the oxygen amount that present. The creation of in-situ DO meter ease the life of a chemist as winkler titration is a tedious procedure to perform DO measurement of water sample. Nowadays, the in-situ DO meter could deliver and perform almost similar result of DO as compared to Winkler titration and hence in-situ DO meter is the first choice of researchers. 

In in-situ DO meter, we do found two major types of technology that present in the market. The first type is called polarographic (aka Clark electrode) method. This is a method invented by Dr Leland Clark in 1956. In 1965, the first biological oxygen monitor is invented and this is a breakthrough technology in medical field. This technology enabled physicians to carry out open-heart surgery for the first time as the real blood oxygen measurements could be recorded during the operation! 

After years of study, another advanced technology called optical or luminescent technology in DO meter has took over the place of polarographic technology. Some researches has chose the DO meter with optical technology due to the easier maintenance and faster warm up time. You may see the differences in between polarographic electrode and optical technology as below. 

Comparison

DO meter with electrode

DO meter with optical

Technology

Polarization technology (old method)

Optical technology (advanced method)

Calibration frequency

Daily

Weekly

Warm up time

10 – 15mins

NO warm up time

Flow dependent

Flow dependent; need to stir manually while using the meter to get actual reading

Flow independent; no need to stir manually while using

Consumables

Membrane cap, filling solution

Membrane cap only

Maintenance

-change the membrance cap

-refill the solution in cap

-check the solution in cap from time to time

-polish the electrode from time to time

- change the membrane cap once the coating of cap wear off; usually can last long up to 12 months or more, depends on usage

Measurement rate    

Faster than optical method
Estimated 8-25 seconds per sample, but subject to the sample condition
Slower than electrode method
Estimated 40 seconds per sample, subject to the sample condition


Tuesday, March 10, 2020

What is pH?

pH value is a figure to indicate acid, neutral or alkaline. pH value being measured from 0-14, in which it does not have any unit for it. The pH is also being defined as the concentration of hydrogen ion, H+ ion in the aqueous solution. The higher the concentration of H+ in the aqueous solution, the more acidic the aqueous sample is. The pH value will tend to be lower than pH 7 and getting lower and lower and close to pH 0.

Normally, pH is being measured/taken by using the following method:
1. litmus paper
2. Color comparator
3. pH meter

The accuracy of pH reading

pH meter > Color comparator > Litmus paper